ChemCalc Dump /sym/1b3f66

id=911657 · host=br.gridbatch.net · 2026-09-03 04:05Z

∑_{k=1}^{n} k = n(n+1)/2

\oint_C \vec{F}\cdot d\vec{r} = 0

252K

\oint_C \vec{F}\cdot d\vec{r} = 0

464K

3z² + 4z + 3 = 0

PV = nRT

32K

∂z/∂φ = 7z

320K

∑_{k=1}^{n} k = n(n+1)/2

e^{i\pi} + 1 = 0

223K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

202K

det| 10 2 ; 6 11 | = 98

e^{i\pi} + 1 = 0

4z² + 9z + 4 = 0

12ω² + 2ω + 4 = 0

∫₀^∞ e^(-z²) dz = √π / 2

F = ma

11y² + 3y + 2 = 0

\frac{4}{3} \sum_{i=1}^{n} i^{2}