ChemCalc Dump /sym/d956be
id=932833 · host=br.gridbatch.net · 2026-09-03 04:03Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
12t² + 3t + 4 = 0
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1α² + 1α + 7 = 0
det| 10 5 ; 1 11 | = 105
det| 7 5 ; 7 8 | = 21
F = ma
∇ × E = −∂B/∂t