ChemCalc Dump /sym/bfd9fa
id=996052 · host=br.gridbatch.net · 2026-09-03 04:02Z
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
252K
\oint_C \vec{F}\cdot d\vec{r} = 0
464K
\lim_{z\to 0} \frac{\sin z}{z} = 1
d/dn [n^11] = 11n^10
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 1 1 ; 7 2 | = -5
det| 1 8 ; 5 2 | = -38
Fe₂O₃ + 3CO → 2Fe + 3CO₂
F = G m₁m₂ / r²
e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0