ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-09-01 11:33Z
4φ² + 1φ + 3 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
202K
\oint_C \vec{F}\cdot d\vec{r} = 0
126K
F = ma
\lim_{t\to 0} \frac{\sin t}{t} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
315K
PV = nRT
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-n²) dn = √π / 2
det| 4 3 ; 3 5 | = 11
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = G m₁m₂ / r²
N₂ + 3H₂ ⇌ 2NH₃