ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:25Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
det| 7 4 ; 4 8 | = 40
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E = mc²
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 6 6 ; 3 7 | = 24
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}